If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4(x-3)(3x+2)^4+5(3x+2)^5/(3x+2)^10=0
Domain of the equation: (3x+2)^10!=0We multiply parentheses ..
x∈R
4(+3x^2+2x-9x-6)^4+5(3x+2)^5/(3x+2)^10=0
We multiply all the terms by the denominator
(4(+3x^2+2x-9x-6)^4)*(3x+2)^10+5(3x+2)^5=0
| (2*5)+3y=31 | | x2+45=18x | | 7/9+x=8/9 | | 9x–5=8x+6 | | 47+2=x+94 | | -28=7(x-17) | | M/12=2x7 | | 9x+25=26 | | 2x-31=2(x+2) | | -3/4x-4=9 | | y-2.56=6.3 | | 3x-21=-3x+21 | | -(15-1)+24+2(5+5p)=0 | | M2=x+94 | | 2–4x+8=18 | | 621=x^2 | | v2+4v-44=0 | | 16t^2+70t+6=-3 | | 4x-(17-9x)=12+1-3x | | x^2+2/15=11/15x | | 4(x–3)=4 | | x(5x^2+14x-24)=0 | | 16=8y-4 | | y-6.8=3.4 | | 500+1/6b=11.25 | | 12x^2-32+5=0 | | 15w+29=8w+57 | | 90=10w | | 10x²-6=9x | | 3b+26=4b+24 | | 5/4x-2/3=1 | | 6p+9=5p+16 |